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JEE PHYSICS MCQ: KINETIC THEORY OF GASES

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For an ideal gas of diatomic molecules

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Correct option: D

{C_p} = \frac{7}{2}R

Option D (

{C_p} = \frac{7}{2}R

) is correct because for a diatomic molecule, the degrees of freedom are 5, and therefore,

C_p = (f/2 + 1)R = (5/2 + 1)R = 7/2 R

.

More Questions from KINETIC THEORY OF GASES

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Assertion: The pressure exerted by an enclosed ideal gas does not depend on the shape of the container.
Reason: The pressure of an ideal gas depends on the number moles, temperature and volume of the enclosed If

c_s

is the velocity of sound in air and

c

is the rms velocity, then Four particles have velocities

1,0,2,3 \mathrm{~m} / \mathrm{s}

. The root mean square of the particles is (in

\mathrm{m} / \mathrm{s}

) The translational degrees of freedom

(f_t)

and rotational degrees of freedom

(f_r)

{CH}_4

molecule are: On any planet, the presence of atmosphere implies (

{C_{rms}} =

= root mean square velocity of molecules and

{V_e} =

escape velocity) At a given temperature, the pressure of an ideal gas of density

\rho

is proportional to