JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

\frac{1}{a}, \frac{1}{b}

and

\frac{1}{c}

are in AP, then

\left(\frac{1}{a}+\frac{1}{b}-\frac{1}{c}\right)

\left(\frac{1}{b}+\frac{1}{c}-\frac{1}{a}\right)

is equal to

View answer and explanation

Correct option: A

\frac{4}{a c}-\frac{3}{b^2}

Option A (

\frac{4}{ac} - \frac{3}{b^2}

) is correct because it is obtained by substituting the AP condition and simplifying the given expression.

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