If $ f(x)=a \log _{e}|x|+b x^{2}+x $ has extremum at $ x=1 $ and $ x=3 $, then

JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

f(x)=a \log _{e}|x|+b x^{2}+x

has extremum at

x=1

and

x=3

, then

View answer and explanation

Correct option: A

a=-3 / 4, b=-1 / 8

Option A (

a=-3 / 4, b=-1 / 8

) is correct because these values satisfy the conditions for the function to have extrema at x=1 and x=3.

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