The value of Planck’s constant is $6.63 \times {10^{ - 34}}\;{\rm{Js}}.$. The velocity of light is $3.0 \times {10^8}{\rm{\;m\;}}{{\rm{s}}^{ - 1}}.$. Which value is closest to the wavelength in nanometre of a quantum of light with frequency of $8 \times {10^{15}}{\rm{\;}}{{\rm{s}}^{ - 1}}?$

NEET UG CHEMISTRY MCQ: STRUCTURE OF ATOM

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The value of Planck’s constant is

6.63 \times {10^{ - 34}}\;\mathrm{Js}.

. The velocity of light is

3.0 \times {10^8}\mathrm{\;m\;}{\mathrm{s}^{ - 1}}.

. Which value is closest to the wavelength in nanometre of a quantum of light with frequency of

8 \times {10^{15}}\mathrm{\;}{\mathrm{s}^{ - 1}}?

View answer and explanation

Correct option: C

4 \times {10^{ - 8}}

Option C is correct. Using the formula λ = c/f, the calculated wavelength is approximately 4 × 10^-8 meters, which is 40 nm.

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