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JEE MATHEMATICS MCQ: ADDITION OF VECTORS

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If 4\widehat \mathbf{i} + 7\widehat \mathbf{j} + 8\mathbf{\hat k},\;2\widehat \mathbf{i} + 3\widehat \mathbf{j} + 4\mathbf{\hat k}\widehat \mathbf{i} + 7\widehat \mathbf{j} + 8\mathbf{\hat k},\;2\widehat \mathbf{i} + 3\widehat \mathbf{j} + 4\mathbf{\hat k} and 2\widehat \mathbf{i} + 5\widehat \mathbf{j} + 7\mathbf{\hat k}2\widehat \mathbf{i} + 5\widehat \mathbf{j} + 7\mathbf{\hat k} are the position vectors of the vertices A,B  and  CA,B\;\mathrm{and\;}C respectively of triangle ABCABC. The position vector of the point where the bisector of angle AA meets BCBC is
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Correct option: A
\frac{1}{2}\left( {6\widehat \mathbf{i} + 13\widehat \mathbf{j} + 18\mathbf{\hat k}} \right)\frac{1}{2}\left( {6\widehat \mathbf{i} + 13\widehat \mathbf{j} + 18\mathbf{\hat k}} \right)
Option A (\frac{1}{2}\left( {6\widehat \mathbf{i} + 13\widehat \mathbf{j} + 18\mathbf{\hat k}} \right)\frac{1}{2}\left( {6\widehat \mathbf{i} + 13\widehat \mathbf{j} + 18\mathbf{\hat k}} \right)) is correct because it represents the position vector of the point where the angle bisector of angle A intersects BC, calculated using the section formula and the angle bisector theorem.

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Let a=i^−j^,b=j^−k^\mathbf{a}=\hat{\mathbf{i}}-\hat{\mathbf{j}}, \mathbf{b}=\hat{\mathbf{j}}-\hat{\mathbf{k}} and c=k^−i^\mathbf{c}=\hat{\mathbf{k}}-\hat{\mathbf{i}}. If d\mathbf{d} is aa unit vector such that a⋅d=0=(bc\mathbf{a} \cdot \mathbf{d}=0=(b \mathbf{c} ) , then d\mathbf{d} is equal to
A vector a⃗{\mathbf{\vec a}} has components 2  p2\;p and 1 with respect to a rectangular cartesian system. This system is rotated through a certain angle about the origin in the counter clockwise sense, if this respect to new system a⃗{\mathbf{\vec a}} has components p+1p + 1 and 1, then If a⃗,b⃗\vec{a}, \vec{b} and c⃗\vec{c} are three mutually perpendicular unit vetors and d⃗\vec{d} is a unit vector which makes equal angles with a→,b→\overrightarrow{\mathrm{a}}, \overrightarrow{\mathrm{b}} ānd c→\overrightarrow{\mathrm{c}} then the value of ∣a→+b→+c→+d→∣2|\overrightarrow{\mathrm{a}}+\overrightarrow{\mathrm{b}}+\overrightarrow{\mathrm{c}}+\overrightarrow{\mathrm{d}}|^2 The non-zero vectors are a⃗,b⃗\vec{a}, \vec{b} and c⃗\vec{c} are related by a⃗=8b⃗\vec{a}=8 \vec{b} and c⃗=−7b⃗\vec{c}=-7 \vec{b}. Then the angle between a⃗\vec{a} and c⃗\vec{c} is If the vectors 2i+j−k,−i+2j+λk2 \mathbf{i}+\mathbf{j}-\mathbf{k},-\mathbf{i}+2 \mathbf{j}+\lambda \mathbf{k} and −5i+2j−k-5 \mathbf{i}+2 \mathbf{j}-\mathbf{k} ar coplanar, then the value of λ\lambda is equal The medium ADAD of the triangle ABCABC is bisected at E,  BEE,\;BE meets ACAC in FF, then AF:AC=AF:AC =
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