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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1
Let f:R→Rf:R \to R be a continuous function satisfying f(x)+f(x+k)=n,f\left( x \right) + f\left( {x + k} \right) = n, for all x∈Rx \in R where k>0k > 0 and nn is a positive integer. If l1=∫04nkf(x)dx{l_1} = \int\limits_0^{4nk} {f\left( x \right)} dx and l2=∫−k3kf(x)dx,{l_2} = \int\limits_{ - k}^{3k} {f\left( x \right)} dx, then
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Correct option: C
l1+nl2=4n2k{l_1} + n{l_2} = 4{n^2}k
Option D (l1+nl2=4n2k{l_1} + n{l_2} = 4{n^2}k) is correct because it is derived from the periodicity of the function and the properties of definite integrals.

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