JEE PHYSICS MCQ: MOTION IN PLANE

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Application +4 | -1

Two forces of

5 \mathrm{~N}

and

7 \mathrm{~N}

act on a particle with an angle of

60^\circ

between them. Find the resultant force.

View answer and explanation

Correct option: A

35^\circ 29'

The correct answer is A (

35^\circ 29'

), which is the angle the resultant force makes with the 5N force, calculated using the formula for the resultant of two vectors.

More Questions from MOTION IN PLANE

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\mathrm{\vec P} = \mathrm{\vec A} + \mathrm{\vec B}\,\,\mathrm{and}\,P = A + B.

\mathrm{\vec A}\,and\,\mathrm{\vec B}

0^{\circ}

90^{\circ}

\mathrm{If}\,(\mathbf{a}+3 \mathbf{b}) \cdot(7 \mathbf{a}-5 \mathbf{b})=0

(\mathbf{a}-4 \mathbf{b}) \cdot(7 \mathbf{a}-2 \mathbf{b})=0

\mathbf{a}

\mathbf{b}

\theta

\left(90^{\circ}-\theta\right)

39.2 \mathrm{~ms}^{-1}

50 \mathrm{~m}

{g}=9.8 \mathrm{~ms}^{-2}