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JEE MATHEMATICS MCQ: PROBABILITY

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If mm rupee coins and nn ten paise coins are placed in a line, then the probability that the extreme coins are ten paise coins, is
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Correct option: B
n(n−1)(m+n)(m+n−1)\frac{{n\left( {n - 1} \right)}}{{\left( {m + n} \right)\left( {m + n - 1} \right)}}
Option B (n(n−1)(m+n)(m+n−1)\frac{{n(n - 1)}}{{(m + n)(m + n - 1)}}) is correct because it represents the probability of selecting a ten paise coin for both extreme positions out of the total possible arrangements.

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