JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1

\lim\limits_{x \to \frac{\pi }{2}}\left(\tan ^2 x\left(\left(2 \sin ^2 x+3 \sin x+4\right)^{\frac{1}{2}}-\left(\sin ^2 x+6 \sin x+2\right)^{\frac{1}{2}}\right)\right)

is equal to

View answer and explanation

Correct option: A

\frac{1}{12}

Option A (

\frac{1}{12}

) is correct because after rationalizing and applying L'Hopital's rule or trigonometric identities, the limit evaluates to

\frac{1}{12}

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