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JEE CHEMISTRY MCQ: ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

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Total number of geometrical isomers in the following compound.
CH3−CH=CH−CH=CH−CH=CH−C6H5C{H_3} - CH = CH - CH = CH - CH = CH - {C_6}{H_5}
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Correct option: D
8
Option D (8) is correct because with three double bonds, each capable of cis/trans isomerism, the total number of geometrical isomers is 23 = 8.

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