${{\rm{B}}_{10}}{{\rm{C}}_2}{{\rm{H}}_{12}}$ is isoelectronic with

${{\rm{B}}_{12}}{\rm{H}}_{12}^{2 - }$

${{\rm{B}}_{12}}{{\rm{H}}_{12}}$

${{\rm{B}}_{12}}{\rm{H}}_{12}^ + $

${{\rm{B}}_{12}}{\rm{H}}_{12}^{2 + }$

NEET UG CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

1 Hard

1 of 1

Application +4 | -1

{\mathrm{B}_{10}}{\mathrm{C}_2}{\mathrm{H}_{12}}

is isoelectronic with

View answer and explanation

Correct option: A

{\mathrm{B}_{12}}\mathrm{H}_{12}^{2 - }

Option A (

{\mathrm{B}_{12}}\mathrm{H}_{12}^{2 - }

) is correct because it has the same number of valence electrons as

{\mathrm{B}_{10}}{\mathrm{C}_2}{\mathrm{H}_{12}}