Which of the following will be the most effective in the coagulation of ${\rm{Fe}}{\left( {{\rm{OH}}} \right)_3}$ sol?

${\rm{M}}{{\rm{g}}_3}{\left( {{\rm{P}}{{\rm{O}}_4}} \right)_2}$

JEE CHEMISTRY MCQ: SURFACE CHEMISTRY

1 Easy

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Application +4 | -1

Which of the following will be the most effective in the coagulation of

\mathrm{Fe}{\left( {\mathrm{OH}} \right)_3}

sol?

View answer and explanation

Correct option: D

\mathrm{M}{\mathrm{g}_3}{\left( {\mathrm{P}{\mathrm{O}_4}} \right)_2}

Option D (

\mathrm{M}{\mathrm{g}_3}{\left( {\mathrm{P}{\mathrm{O}_4}} \right)_2}

) is correct because according to the Hardy-Schulze rule, ions with higher charges are more effective in coagulation, and

PO_4^{3-}

has the highest negative charge.