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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
For x>0x > 0, if f(x)=∫1xlog⁡et(1+t)dtf(x) = \int\limits_1^x {\frac{{{{\log }_e}t}}{{\left( {1 + t} \right)}}dt} then f(e)+f(1e) f(e) + f\left( {\frac{1}{e}} \right)\, is equal to
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Correct option: C
12\frac{1}{2}
Option C (12\frac{1}{2}) is correct because after evaluating the integrals and using substitution, the expression simplifies to 1/2.

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