Identify the correct statement for change of Gibb’s energy for a system ($\Delta {G_{{\rm{system}}}}$) at constant temperature and pressure:

If $\Delta {G_{{\rm{system}}}}$=0, the system has attained equilibrium

If $\Delta {G_{{\rm{system}}}}$=0, the system is still moving in a particular direction

If $\Delta {G_{{\rm{system}}}}$=-ve, the process is not spontaneous

If $\Delta {G_{{\rm{system}}}}$=+ve, the process is spontaneous

NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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Understanding +4 | -1

Identify the correct statement for change of Gibb’s energy for a system (

\Delta {G_{\mathrm{system}}}

) at constant temperature and pressure:

View answer and explanation

Correct option: D

\Delta {G_{\mathrm{system}}}

=0, the system has attained equilibrium

Option D (If

\Delta {G_{\mathrm{system}}}

=0, the system has attained equilibrium) is correct because at equilibrium, the change in Gibbs free energy is zero.