Skip to main content
Back to SYSTEM OF CIRCLES

JEE MATHEMATICS MCQ: SYSTEM OF CIRCLES

1 Easy
1 of 1
Application +4 | -1
The equation of the circle and its chord are respectively x2+y2=a2x^2+y^2=a^2 and xcos⁡α+ysin⁡α=px \cos \alpha+y \sin \alpha=p. The equation of the circle of which this chord is a diameter, is
View answer and explanation
Correct option: A
x2+y2−2pxcos⁡α−2pysin⁡α+2p2−a2=0x^2+y^2-2 p x \cos \alpha-2 p y \sin \alpha+2 p^2-a^2=0
Option A (x2+y2−2pxcos⁡α−2pysin⁡α+2p2−a2=0x^2+y^2-2 p x \cos \alpha-2 p y \sin \alpha+2 p^2-a^2=0) is correct because it represents the equation of a circle where the given chord is a diameter, derived using the concept of a family of circles.

More Questions from SYSTEM OF CIRCLES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.