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JEE PHYSICS MCQ: ELECTROMAGNETIC WAVES

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Application +4 | -1
A cylindrical region of radius 1.2 m1.2 \mathrm{~m} is containing a uniform electric field that is increasing uniformly with time. At t=0\mathrm{t}=0 the field is zero and at t=5.0 s\mathrm{t}=5.0 \mathrm{~s} the field is 200 V/m.200 \mathrm{~V} / \mathrm{m}. The total displacement current through a cross section of the region is:
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Correct option: D
1.6×10−9 A1.6 \times 10^{-9} \mathrm{~A}
Option D (1.6×10−9 A1.6 \times 10^{-9} \mathrm{~A}) is correct because the displacement current is calculated using the formula id=ε0dϕEdt=ε0AdEdti_d =\varepsilon_0 \frac{d \phi_E}{d t} = \varepsilon_0 {A} \frac{d E}{d t}.

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