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JEE CHEMISTRY MCQ: d & f- BLOCK ELEMENTS

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The behaviour of samarium (Z=62) is very much
like europium (Z=63). Since both elements:
View answer and explanation
Correct option: A
exhibit +2 and +3 oxidation states
Option A (exhibit +2 and +3 oxidation states) is correct because both Samarium and Europium readily exhibit +2 and +3 oxidation states due to their electronic configurations and stability of half-filled/fully-filled f-orbitals.

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