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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Hard
1 of 1
Application +4 | -1
∫π3π2[2sin⁡x]dx=−5πk\int\limits_\pi^{\frac{3 \pi}{2}}[2 \sin x] d x=\frac{-5 \pi}{k} (where [.] is GIF) then k=\mathrm{k}=
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Correct option: A
6
Option A (6) is correct because the integral evaluates to −5π6\frac{{-5 \pi}}{{6}}, thus k = 6.

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