Skip to main content
Back to STATISTICS

JEE MATHEMATICS MCQ: STATISTICS

1 Easy
1 of 1
Analyzing +4 | -1
For the arithmetic progression a,(a+d),(a+2d),(a+3d),……,(a+2nd)a,\left( {a + d} \right),\left( {a + 2d} \right),\left( {a + 3d} \right), \ldots \ldots ,\left( {a + 2nd} \right), the mean deviation from mean is
View answer and explanation
Correct option: B
n(n+1)d2n+1\frac{{n\left( {n + 1} \right)d}}{{2n + 1}}
Option B (n(n+1)d2n+1\frac{{n\left( {n + 1} \right)d}}{{2n + 1}}) is correct because the mean deviation from the mean for the given arithmetic progression is calculated to be this value.

More Questions from STATISTICS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.