Let ${x_i}(1 \le \,i\, \le \,10)$ be ten observations of a random variable $X.\,{\rm{If}}\,\sum\limits_{i = i}^{10} {({x_i} - p)} \, = \,3\,{\rm{and}}\,\sum\limits_{i = i}^{10} {{{({x_i} - p)}^2}\, = \,9\,\,} $ $p$ where ${\rm{0}} \ne \,p \in R,$ then the standard deviation of these observation is

JEE MATHEMATICS MCQ: STATISTICS

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Application +4 | -1

Let

{x_i}(1 \le \,i\, \le \,10)

be ten observations of a random variable

X.\,\mathrm{If}\,\sum\limits_{i = i}^{10} {({x_i} - p)} \, = \,3\,\mathrm{and}\,\sum\limits_{i = i}^{10} {{{({x_i} - p)}^2}\, = \,9\,\,}

p

where

\mathrm{0} \ne \,p \in R,

then the standard deviation of these observation is

View answer and explanation

Correct option: A

\frac{9}{{10}}

Option A (

\frac{9}{{10}}

) is correct because it is the standard deviation calculated from the given summations.

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