NEET UG CHEMISTRY MCQ: SURFACE CHEMISTRY

1 Medium

1 of 1

Application +4 | -1

Plot of

\log \frac{x}{m}

against

\log p

is a straight line inclined at an angle of

45^\circ

. When the pressure is 0.5 atm and Freundlich parameter,

k

is 10, the amount of solute adsorbed per gram of adsorbent will be (log 5=0.6990)

View answer and explanation

Correct option: D

5\mathrm{ }\;g

Option D (5 g) is correct because, with a 45-degree angle, 1/n = 1, and the equation simplifies to x/m = kp, resulting in 5 g when the values are substituted.

More Questions from SURFACE CHEMISTRY

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A cationic colloidal electrolyte forms micelle at

10^{-3} \mathrm{M}

concentration in water. Its

1 \mathrm{~mm}^3

solution contains

2 \times 10^{13}

micelle structures. What is the number of cations contained in one micelle? Take

\mathrm{N}_{\mathrm{A}}=6 \times 10^{23}

. Graph between

\log \frac{{x}}{{m}}

and

\log {P}

is a straight line inclined at an angle

\theta=45^{\circ}

. When pressure is

0.5

atm and

\log {k}= 0.699,

the amount of solute adsorbed per

\mathrm{g}

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\log \;x/m\mathrm{ } \;vs.

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. If

{1.9 \times {{10}^{ - 4}}\;\mathrm{g}}

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