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JEE MATHEMATICS MCQ: PROBABILITY

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Application +4 | -1

The value of

C

for which

P\left( {X = k} \right) = C\;{k^2}

can serve as the probability function of a random variable

X

that takes value 0, 1, 2, 3, 4 is

View answer and explanation

Correct option: A

\frac{1}{{30}}

Option A (

\frac{1}{{30}}

) is correct because it is the value of C that makes the sum of probabilities equal to 1, satisfying the condition for a probability function.

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\begin{array}{cccccc}X: & 1 & 2 & 3 & 4 & 5 \\ P(X): & k^2 & 2 k & k & 2 k & 5 k^2\end{array}

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B

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