JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

1 of 1

Analyzing +4 | -1

The values of

x

between

\mathrm{\;0}

and

2\,\pi

which satisfy the equation

\sin \,\,x\,\sqrt {8\,\,{{\cos }^2}\,\,x} = 1

are in AP. The common difference of the AP is

View answer and explanation

Correct option: B

\frac{\mathrm{\pi }}{4}

Option B (

\frac{\mathrm{\pi }}{4}

) is correct because the values of x that satisfy the equation form an arithmetic progression with a common difference of

\frac{\mathrm{\pi }}{4}

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\mathrm{X}

\theta \rightarrow \frac{\pi}{2}

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0 < x < \pi

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