JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Analyzing +4 | -1

f(x)=\frac{(2 x+3)(\sqrt{x}-1)}{2 x^2+x-3}

then

\lim _{x \rightarrow 1} f(x)

is equal to

View answer and explanation

Correct option: D

-\frac{1}{10}

Option D (-1/10) is correct because after simplifying the expression and taking the limit as x approaches 1, the result is -1/10.

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