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JEE MATHEMATICS MCQ: CIRCLES

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Application +4 | -1

The range of values of '

a

' such that the angle

\theta

between the pair of tangents drawn from

(a, 0)

to the circle

x^2+y^2=1

satisfies

\frac{\pi}{2} < \theta < \pi

, is

View answer and explanation

Correct option: D

(-\sqrt{2},-1) \cup(1, \sqrt{2})

Option D (

(-\sqrt{{2}},-1) \cup (1, \sqrt{{2}})

) is correct because the condition

\frac{{\pi}}{{2}} < \theta < \pi

implies that

\tan \theta < 0

, which leads to the given range for 'a'.

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