The coefficient of $x^{60}$ in $(1+x)^{51}\left(1-x+x^2\right)^{50}$ is

$-\left({ }^{50} C_{20}\right)$

$-\left({ }^{51} C_{20}\right)$

JEE MATHEMATICS MCQ: BINOMIAL THEOREM

1 Easy

1 of 1

Analyzing +4 | -1

The coefficient of

x^{60}

(1+x)^{51}\left(1-x+x^2\right)^{50}

View answer and explanation

Correct option: A

{ }^{50} C_{20}

Option A (

{ }^{50} C_{20}

) is correct because

(1+x)^{51}(1-x+x^2)^{50}

simplifies to

(1+x)(1+x^3)^{50}

, and the coefficient of

x^{60}

{ }^{50} C_{20}

Practice All Chapter MCQs →

\left({ }^{10} C_0\right)^2-\left({ }^{10} C_1\right)^2+\ldots-\left({ }^{10} C_9\right)^2+\left({ }^{10} C_{10}\right)^2

a

d

\left( {n + 1} \right)

a{C_0} - \left( {a + d} \right){C_1} + \left( {a + 2d} \right){C_2} - ... + ...

(1-x)^{201}\left(1+x+x^2\right)^{200}

\left(\frac{1}{x}+2 x\right)^n

{x^5}

\frac{{1 + {x^2}}}{{1 + x}},\left| x \right| < 1,

\left(\begin{array}{c}2 n+1 \\ 0\end{array}\right)+\left(\begin{array}{c}2 n+1 \\ 3\end{array}\right)+\left(\begin{array}{c}2 n+1 \\ 6\end{array}\right)+\ldots=170

n