Skip to main content
Back to d & f- BLOCK ELEMENTS

JEE CHEMISTRY MCQ: d & f- BLOCK ELEMENTS

1 Medium
1 of 1
Analyzing +4 | -1
(X)+K2CO3+Air⟶heat(Y)(X)+K_2 {CO}_3+\mathrm{Air} \stackrel{\mathrm{heat}}{\longrightarrow}(Y)

(Y)+Cl2→(Z)(Y)+Cl_2 \rightarrow(Z) Pink

Which of the following is correct
View answer and explanation
Correct option: C
X={X}= black, MnO2,Y={MnO}_2, {Y}= green, K2MnO4,Z=KMnO4{K}_2 {MnO}_4, {Z}={KMnO}_4
Option C (X={X}= black, MnO2,Y={MnO}_2, {Y}= green, K2MnO4,Z=KMnO4{K}_2 {MnO}_4, {Z}={KMnO}_4) is correct because MnO2MnO_2 reacts with K2CO3K_2CO_3 in the presence of air to form green K2MnO4K_2MnO_4, which then reacts with Cl2Cl_2 to form pink KMnO4KMnO_4.

More Questions from d & f- BLOCK ELEMENTS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.