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JEE CHEMISTRY MCQ: CHEMICAL KINETICS

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An organic compound A decomposes the following two parallel first-order reactions A→K1B\mathrm{A} \xrightarrow{K_1} \mathrm{B} and A→K2C.\mathrm{A} \xrightarrow{K_2} \text{C}. If K1K_1 is 1.25×10−5 s−11.25 \times 10^{-5} \mathrm{~s}^{-1} and K1K2=19,\frac{K_1}{K_2}=\frac{1}{9}, then the value of [C][A]\frac{[\mathrm{C}]}{[\mathrm{A}]} after one hour of start of reaction by taking only A,\mathrm{A}, is (ln⁡1.568=0.45)(\ln 1.568=0.45)
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Correct option: B
0.51120.5112
Option B (0.5112) is correct because it is calculated using the integrated rate laws for parallel first-order reactions, considering the ratio of rate constants and the reaction time.

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The reaction A2+B2→2AB\mathrm{A}_2+\mathrm{B}_2 \rightarrow 2 \mathrm{AB} follows the mechanism

A2⇌k−1k1A+A (fast) A+B2→k2AB+B (slow) A+B→AB (fast) \begin{aligned} & {{\text{A}}_2}\mathop \rightleftharpoons \limits_{{{\text{k}}_{ - 1}}}^{{{\text{k}}_1}} {\text{A}} + {\text{A (fast) }} \\ & \mathrm{A}+\mathrm{B}_2 \xrightarrow{\mathrm{k}_2} \mathrm{AB}+\mathrm{B} \text { (slow) } \\ & \mathrm{A}+\mathrm{B} \rightarrow \mathrm{AB} \text { (fast) } \end{aligned}

The overall order of the reaction is:
For the first order reaction with the rate constant kk, which expression gives the rate half-life period? (Initialconc.=a)(Initial\mathrm{ }conc.\mathrm{ } = a) Which of the following is a zero order reaction? For a certain reaction involving a single reactant, it is found that C0TC_0 \sqrt{T} is constant, where C0C_0 is the initial concentration of the reactant and TT is the half-life. What is the order of the reaction? Arrhenius equation is The energy of activation for an uncatalysed reaction is 100 kJ/mol.100 \mathrm{~kJ/mol}. Presence of a catalyst lowers the energy of activation by 75%75 \%. The log⁡10K2K1\log _{10} \frac{K_2}{K_1} of the ratio of rate constant of catalysed and uncatalysed reactions at 27∘C27^{\circ} \mathrm{C} is?

Assume the frequency factor is same for both reactions. (Given 2.303×8.314=19.1472.303 \times 8.314=19.147)
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