Skip to main content
Back to UNITS & MEASUREMENTS

JEE PHYSICS MCQ: UNITS & MEASUREMENTS

1 Medium
1 of 1
Analyzing +4 | -1
In two systems of relations among velocity, acceleration and force are respectively v2=α2βv1v_2=\frac{\alpha^2}{\beta} v_1, a2=αβa1a_2=\alpha \beta a_1 and F2=F1αβF_2=\frac{F_1}{\alpha \beta}. If α\alpha and β\beta are constants then relations among mass, length and time in two systems are
View answer and explanation
Correct option: B
M2=1α2β2M1,L2=α3β3L1,T2=T1αβ2M_2=\frac{1}{\alpha^2 \beta^2} M_1, L_2=\frac{\alpha^3}{\beta^3} L_1, T_2=T_1 \frac{\alpha}{\beta^2}
Option B is correct because the relations among mass, length, and time can be derived from the given relations among velocity, acceleration, and force.

More Questions from UNITS & MEASUREMENTS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.