JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Analyzing +4 | -1

Let

f: R \rightarrow[0, \infty)

be such that

\lim \limits_{{x \rightarrow 5}} f(x)

exists and

\lim \limits_{{x \rightarrow 5}} \frac{(f(x))^2-9}{\sqrt{|x-5|}}=0

. Then,

\lim \limits_{{x \rightarrow 5}} f(x)

equals

View answer and explanation

Correct option: C

Option C (3) is correct because the limit of f(x) as x approaches 5 must be 3, given the provided condition and the non-negativity of f(x).

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