JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1

a, b, c, k

are real constants and

\alpha, \beta, \gamma

are real variables and

a \tan \alpha+b \tan \beta+c \tan \gamma=k

then the minimum value of

\tan ^2 \alpha+\tan ^2 \beta+\tan ^2 \gamma

View answer and explanation

Correct option: D

\frac{k^2}{a^2+b^2+c^2}

Option D (

\frac{{k^2}}{{a^2+b^2+c^2}}

) is correct because it is derived from Cauchy-Schwarz inequality applied to the given equation.

More Questions from FUNCTIONS

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