Question

If

\cos \,\,\frac{x}{2}\,\,.\,\,\cos \,\,\frac{x}{{{2^2}}} \ldots ..\cos \,\,\frac{x}{{{2^n}}} = \frac{{\sin \,\,x}}{{{2^n}\,\,\sin \;\,\,\frac{x}{{{2^n}}}}}

, then

\frac{1}{2}\,\,\tan \,\,\frac{x}{2} + \frac{1}{{{2^2}}}\,\,\tan \,\,\frac{x}{{{2^2}}} + ... + \frac{1}{{{2^n}}}\,\,\tan \,\,\frac{x}{{{2^n}}}

is

Accepted Answer

$\frac{1}{{{2^n}}}\,\,\cot \,\,\left( {\frac{x}{{{2^n}}}} \right) - \cot \,\,x$

Answer

$\cot \,\,x - \cot \,\,\frac{x}{{{2^n}}}$

Answer

$\frac{1}{{{2^n}}}\,\,	an \,\,\left( {\frac{1}{{{2^n}}}} ight) - 	an \,\,x$

Answer

$\frac{1}{2}\,\,\cot \,\,x - \frac{1}{{{2^n}}}\,\,\cot \,\,\left( {\frac{x}{{{2^n}}}} \right)$

JEE MATHEMATICS MCQ: MULTIPLE AND SUBMULTIPLE ANGLES

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