JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

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Application +4 | -1

Let

a_n

be the

n

th term of the G.P. of positive numbers. Let

\sum\limits_{{n=1}}^{100} a_{2 n}-\alpha

and

\sum\limits_{{n=1}}^{100} a_{2 n-1}-\beta

, such that

\alpha \neq \beta

, then the common ratio is

View answer and explanation

Correct option: A

\frac{\alpha}{\beta}

Option A (

\frac{\alpha}{\beta}

) is correct because the common ratio is found by dividing the sum of even-indexed terms by the sum of odd-indexed terms in the G.P.

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