JEE CHEMISTRY MCQ: CHEMICAL KINETICS

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Analyzing +4 | -1

Dinitropentoxide decomposes as follows:

\mathrm{N}_2 \mathrm{O}_5(\mathrm{g}) \longrightarrow 2 \mathrm{NO}_2(\mathrm{g})+\frac{1}{2} \mathrm{O}_2(\mathrm{g})

Given:

\begin{aligned} & \mathrm{d}\left[\mathrm{N}_2 \mathrm{O}_5\right] / \mathrm{dt}=\mathrm{k}_1\left[\mathrm{N}_2 \mathrm{O}_5\right] \\ & \mathrm{d}\left[\mathrm{NO}_2\right] / \mathrm{dt}=\mathrm{k}_2\left[\mathrm{N}_2 \mathrm{O}_5\right] \\ & \mathrm{d}\left[\mathrm{O}_2\right] / \mathrm{dt}=\mathrm{k}_3\left[\mathrm{N}_2 \mathrm{O}_5\right] \end{aligned}

What is the relation between

\mathrm{k}_1, \mathrm{k}_2

and

\mathrm{k}_3

View answer and explanation

Correct option: A

4 \mathrm{k}_3

Option A (

4k_3

) is correct because the rate constants are related by the stoichiometry of the reaction.

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\mathrm{A}_2+\mathrm{B}_2 \rightarrow 2 \mathrm{AB}

\begin{aligned} & {{\text{A}}_2}\mathop \rightleftharpoons \limits_{{{\text{k}}_{ - 1}}}^{{{\text{k}}_1}} {\text{A}} + {\text{A (fast) }} \\ & \mathrm{A}+\mathrm{B}_2 \xrightarrow{\mathrm{k}_2} \mathrm{AB}+\mathrm{B} \text { (slow) } \\ & \mathrm{A}+\mathrm{B} \rightarrow \mathrm{AB} \text { (fast) } \end{aligned}

k

(Initial\mathrm{ }conc.\mathrm{ } = a)

C_0 \sqrt{T}

C_0

T

100 \mathrm{~kJ/mol}.

75 \%

\log _{10} \frac{K_2}{K_1}

27^{\circ} \mathrm{C}

2.303 \times 8.314=19.147