$\mathop {\lim }\limits_{x \to 0} \frac{{{e^{{x^2}}} - \cos x}}{{{x^2}}}$ is equal to

JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Application +4 | -1

\lim\limits_{x \to 0} \frac{{{e^{{x^2}}} - \cos x}}{{{x^2}}}

is equal to

View answer and explanation

Correct option: D

\frac{3}{2}

Option D (

\frac{3}{2}

) is correct because by applying L'Hopital's rule twice, the limit evaluates to 3/2.

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