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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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If x=∑n=0∞an,y=∑n=0∞bn,z=∑n=0∞cn,x = \sum\limits_{n = 0}^\infty {{a^n}} ,y = \sum\limits_{n = 0}^\infty {{b^n}} ,z = \sum\limits_{n = 0}^\infty {{c^n}} , where a,b,ca,b,c are in A.P and ∣a∣<1,∣b∣<1,∣c∣<1,  abc≠0,\left| a \right| < 1,\left| b \right| < 1,\left| c \right| < 1,\,\,abc \ne 0, then
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Correct option: C
1x,1y,1z\frac{1}{x},\frac{1}{y},\frac{1}{z} are in A.P.
Option C (1x,1y,1z\frac{1}{x},\frac{1}{y},\frac{1}{z} are in A.P.) is correct because if a, b, c are in A.P., then their reciprocals with a constant subtracted are in Harmonic Progression, implying x, y, z are in H.P., and therefore their reciprocals are in A.P.

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