JEE MATHEMATICS MCQ: 2D GEOMETRY SYSTEM

1 Easy

1 of 1

Application +4 | -1

The locus of the point

(\sqrt{(3 h+2)}, \sqrt{3 k})

. If

(h, k)

lies on

x+y=1

View answer and explanation

Correct option: B

A circle

Option B (A circle) is correct because substituting

h = \frac{{x_1^2 - 2}}{{3}}

and

k = \frac{{y_1^2}}{{3}}

into

h + k = 1

results in the equation of a circle:

x^2 + y^2 = 5

More Questions from 2D GEOMETRY SYSTEM

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\alpha

(\alpha, 2 \alpha)

\Delta A B C

A(0,2), B(2,0)

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P

2 P A=3 P B

A

(0,0)

B

(4,-3)

(1, \sqrt{3}),(0,0)

(2,0)

(1,5),(-3,1) \,\&\,(-2,1)

9 x^2-16 y^2-18 x+32 y-23

=0

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