JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1

\lim\limits_{x \to 0} \frac{4}{{{x^8}}}\left( {1 - \cos \frac{{{x^2}}}{2} - \cos \frac{{{x^2}}}{4} + \cos \frac{{{x^2}}}{2} \cdot \cos \frac{{{x^2}}}{4}} \right) = {\left( {\frac{1}{{{n_1}}}} \right)^n}

Where

{n_1}

is a Prime number, then value of

n_1+n

equals

View answer and explanation

Correct option: A

The correct answer is A. By simplifying the limit using trigonometric identities and standard limit results, the value of

n_1 + n

is found to be 8.

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