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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1
Let Sn=113+1+213+23+1+2+313+23+33+…S_{n}=\frac{1}{1^{3}}+\frac{1+2}{1^{3}+2^{3}}+\frac{1+2+3}{1^{3}+2^{3}+3^{3}}+\ldots. +1+2+……+n13+23+……+n3+\frac{1+2+\ldots \ldots+n}{1^{3}+2^{3}+\ldots \ldots+n^{3}}, If 100Sn=n100 \mathrm{S}_{n}=n, then n\mathrm{n} is equal to:
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Correct option: A
199
Option A (199) is correct because simplifying the series allows us to find a closed form and solve for n.

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