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JEE PHYSICS MCQ: GRAVITATION

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According to Kelper’s law of planetary motion if T represent time period and

r

is orbital radius, then for two planets these are related as

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Correct option: D

{\left( {\frac{{{T_1}}}{{{T_2}}}} \right)^2} = {\left( {\frac{{{r_1}}}{{{r_2}}}} \right)^3}

Option D (

{\left( {\frac{{{T_1}}}{{{T_2}}}} \right)^2} = {\left( {\frac{{{r_1}}}{{{r_2}}}} \right)^3}

) is correct because it represents Kepler's Third Law, which states that the square of the period is proportional to the cube of the orbital radius.

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