Skip to main content
Back to SEQUENCE OF SERIES

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy
1 of 1
Application +4 | -1
If 12+22+…+n2=10151^2+2^2+\ldots+n^2=1015, then value of nn is
View answer and explanation
Correct option: B
14
Option B (14) is correct. By using the formula for the sum of squares and solving the resulting equation, we find n = 14.

More Questions from SEQUENCE OF SERIES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.