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JEE MATHEMATICS MCQ: PERMUTATIONS

1 Easy

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The number of ways in which 10 candidates

A_1, A_2, \ldots

,

A_{10}

can be ranked so that

A_1

is always above

A_2

, is

View answer and explanation

Correct option: B

\frac{10 \text { ! }}{2}

The correct answer is B (

\frac{{10 \text { ! }}}{{2}}

) because half of the total permutations will have

A_1

above

A_2

, and the other half will have

A_2

above

A_1

.

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