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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

1 Medium

1 of 1

Application +4 | -1

The work done in placing a charge of

8 \times 10^{-18}

coulomb on a condenser of capacity 100 micro-farad is

View answer and explanation

Correct option: A

32 \times 10^{-32}

Joule

Option A (

32 \times 10^{-32}

Joule) is correct because the work done is equal to the energy stored in the capacitor, which can be calculated using the formula

W = \frac{{Q^2}}{{2C}}

.

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