JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1

0 \leq x \leq \frac{\pi}{2}

and

81^{\sin ^2 x}+81^{\cos ^2 x}=30

, then

x

is equal to

View answer and explanation

Correct option: A

\frac{\pi}{6}, \frac{\pi}{3}

Option A (

\frac{\pi}{6}, \frac{\pi}{3}

) is correct because solving the given equation by substituting

y = 81^{\sin^2 x}

leads to finding the values of

\sin x

and hence

x

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