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JEE MATHEMATICS MCQ: RATE MEASURE

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Application +4 | -1

A particle moves along a straight line according to the law

s = 16 - 2t + 3{t^3}

, where

s

a metre is the distance of the particle from a fixed point at the end of

t

seconds. The acceleration of the particle at the end of

2s

is

View answer and explanation

Correct option: A

36m/{s^2}

Option A (

36m/{s^2}

) is correct because it is the acceleration calculated by taking the second derivative of the position function and evaluating it at t=2s.

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