JEE MATHEMATICS MCQ: ELLIPSE

1 Easy

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Application +4 | -1

If polar of

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1

is always touching the circle

x^2+y^2=c^2

, then locus of pole is

View answer and explanation

Correct option: A

c^2\left(a^4 y^2+b^4 x^2\right)=a^4 b^4

Option B (

c^2(a^4 x^2+b^4 y^2)=a^4 b^4

) is correct because the polar of the ellipse touches the circle, so the condition for tangency can be used to find the locus of the pole.

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