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JEE MATHEMATICS MCQ: PERMUTATIONS

1 Easy

1 of 1

Application +4 | -1

If

{P_m}

stands for

{\;^m}{P_m}

, then

1 + 1{P_1} + 2{P_2} + 3{P_3} + ... + n.{P_n}

is equal to

View answer and explanation

Correct option: D

\left( {n + 1} \right)!

Option D (

\left( {n + 1} \right)!

) is correct because the given sum simplifies to (n+1)!.

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