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JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1
sin⁡2A+sin⁡2B−sin⁡2C=\sin ^2 A+\sin ^2 B-\sin ^2 C=
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Correct option: D
2sin⁡Asin⁡Bcos⁡C2 \sin A \sin B \cos C
Option D (2sin⁡Asin⁡Bcos⁡C2 \sin A \sin B \cos C) is correct because by using trigonometric identities and sum-to-product formulas, the expression simplifies to the given form.

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