If $0 < x < \frac{\pi}{2}$, then

JEE MATHEMATICS MCQ: INCREASING & DECREASING

1 Easy

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Analyzing +4 | -1

0 < x < \frac{\pi}{2}

, then

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Correct option: D

None of these

The correct answer is D (None of these) because for

0 < x < \frac{{\pi}}{{2}}

, the correct inequality is

\sin x < x < \tan x

Practice All Chapter MCQs →

f\left( x \right) = \frac{{K\sin x + 2\cos x}}{{\sin x + \cos x}}

x

f\left( x \right) = {x^2} + ax + 1

a

f(x)=

\sin x-\cos x-a x+b

f(x)=x e^{x(1-x)}, x \in R

f

g

fog

f\left( x \right) = {x^3} + b{x^2} + cx + d

0 < {b^2} < c

\left( { - \infty ,\;\infty } \right)