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JEE MATHEMATICS MCQ: LIMITS

1 Easy
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Analyzing +4 | -1
If lim⁡x→2tan⁡(x−2){x2+(k−2)x−2k}x2−4x+4=5\lim _{x \rightarrow 2} \frac{\tan (x-2)\left\{x^2+(k-2) x-2 k\right\}}{x^2-4 x+4}=5
then kk is equal to:
View answer and explanation
Correct option: D
3
Option D (3) is correct because the limit can be evaluated by factoring and using the standard limit for tan(x)/x.

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